Project Euler Problem 6

2014年04月09日

Q:

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The sum of the squares of the first ten natural numbers is,12 + 22 + … + 102 = 385
The square of the sum of the first ten natural numbers is,(1 + 2 + … + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

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R

First Version

item <- 1:100
print(sum(item)^2-sum(item^2))